Find the depth at which the value of g becomes 25% of that at the surface of the earth . (Radius of the earth = 6400 km)

Find the depth at which the value of g becomes 25% of that at the surf

1.	Find the depth at which the value of g becomes 25% of that at the surface of the earth . (Radius of the earth = 6400 km)
Answer» Solution :g at a DEPTH , `g_(d) =g (1-d/R)` In this problem , `g_(d) = (25)/100 g = 0.25 g ` Substituting `g_(d)=0.25g and R = 6400` KM we get d = 4800 km