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Find the derivation of function(x4 – 6x3 + 7x2 + 4x + 2) (x3 – 1) |
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Answer» Let u = x4 – 6x3 + 7x2 + 4x + 2 and v = x3 – 1 u’ = 4x3 – 6(3x2) + 7(2x) + 4(1) + 0 = 4x3 – 18x2 + 14x + 4 v’ = 3x3 y = uv’ + vu’ i.e. dy/dx = (x4 – 6x3 + 7x2 + 4x + 2) (3x2) + (x3 – 1) (4x3 – 18x2 + 14x + 4) = 3x6 – 18x5 + 21x4 + 12x3 + 6x2 + 4x6 – 18x5 + 14x4 + 4x3 – 4x3 + 18x2 – 14x – 4 = 7x6 – 36x5 + 35x4 + 12x3 + 24x2 – 14x – 4 |
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