Saved Bookmarks
| 1. |
Find the derivative:r = (2 tan3 2y - 1)1/2 |
|
Answer» \(r = 2(tan^3\, 2y-1 )^{\frac12}\) \(\frac{dr}{dy}= 2\times\frac12(tan^32y-1)^\frac{-1}2 \,\frac{d}{dy}(tan^32y-1)\) \(= (tan^32y - 1)^\frac{-1}{2} (3\times2\,tan^22y \,sec^22y)\) \(=6\, tan^22y\,sec^22y(tan^32y - 1)^{\frac{-1}{2}}\) |
|