1.

Find the derivative:v = (1 - 4 cos 5y)-1/2

Answer»

\(v = (1 - 4 \,cos\,5y)^{\frac{-1}{2}}\)

\(\frac{dv}{dy} = \frac{-1}{2}(1 - 4\,cos\,5y)^{\frac{-3}2} \,\frac d{dy}(1 - 4\,cos \,5y)\)

\(= \frac{-1}{2}(1 -4\, cos \,5y)^{\frac{-3}2} \,x -4x - 5 sin\,5y\)

\(= - 10 \,sin\,5y(1 -4 \,cos\,5y)^{\frac{-3}{2}}\)



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