1.

Find the derivatives of the function with respect to corresponding independent variables.y = e-x. log x

Answer»

y = e-x log x = uv (say) 

Here u = e-x and v = log x 

⇒ u’ = -e-x and v’ = 1/x

Now y = uv ⇒ y’ = uv’ + vu’

(i.e.) dy/dx = e-x (1/x) + log(-e-x)

= e-x(1/x - log x)



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