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Find the derivatives of the function with respect to corresponding independent variables.y = e-x. log x |
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Answer» y = e-x log x = uv (say) Here u = e-x and v = log x ⇒ u’ = -e-x and v’ = 1/x Now y = uv ⇒ y’ = uv’ + vu’ (i.e.) dy/dx = e-x (1/x) + log(-e-x) = e-x(1/x - log x) |
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