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Find the differential equation corresponding to the equation `y=Ae^(2x)+Be^(-x)`. |
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Answer» `y=Ae^(2x)+Be^(-x)`……….`(1)` `implies (dy)/(dx)=2Ae^(2x)+Be^(-x)`………`(2)` `implies (d^(2)y)/(dx^(2))=4Ae^(2x)+Be^(-x)`………….`(3)` Adding eqs. `(1)` and `(2)` `(dy)/(dx)+y=3Ae^(2x)` ……………`(4)` Adding eqs. `(2)` and `(3)` `(d^(2)y)/(dx^(2))+(dy)/(dx)=6A*e^(2x)` `implies (d^(2)y)/(dx^(2))+(dy)/(dx)=2((dy)/(dx)+y)` [From eq. `(4)`] `implies (d^(2)y)/(dx^(2))-(dy)/(dx)-2y=0`. |
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