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Find the differential equation of the family ofcurves `y=A e^(2x)+B e^(-2x)`, where A and B are arbitrary constants. |
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Answer» Correct Answer - `(d^(2)y)/(dx^(2))=4y` `y=Ae^(2x)+Be^(-2x)` `therefore (dy)/(dx)=2Ae^(2x)-2Be^(-2x)` or `(d^(2)y)/(dx^(2))=4Ae^(2x)+4Be^(-2x)` = `4(Ae^(2x)+Be^(-2x))` `=4y`, which is the required differential equation. |
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