1.

Find the dimension of B2/2μ0(1) ML-1T-2(2) ML2T-2(3) ML-1T2(4) ML-2T-1

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Answer is (1)

Energy density in magnetic field = B2/2μ0

= {Force x displacement}/{(displacement)3}

= {MLT-2.L}/{L3} = ML-1T-2



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