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Find the dimension of B2/2μ0(1) ML-1T-2(2) ML2T-2(3) ML-1T2(4) ML-2T-1 |
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Answer» Answer is (1) Energy density in magnetic field = B2/2μ0 = {Force x displacement}/{(displacement)3} = {MLT-2.L}/{L3} = ML-1T-2 |
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