Find the dimensions of a/b in the equation. F=asqrtx+bt^(2) where F is force, x is distance and t is time.

Find the dimensions of a/b in the equation. F=asqrtx+bt^(2) where F is

1.	Find the dimensions of a/b in the equation. F=asqrtx+bt^(2) where F is force, x is distance and t is time.
Answer» SOLUTION :`[asqrtx]=[F]` `therefore [a]=([F])/([SQRTX])=(MLT^(-2))/(L^(1//2))=ML^(1//2)T^(-2)` `[BT^(2)]=[F]` `therefore [b]=([F])/([t^(2)])=(MLT^(-2))/(T^(2))` `=MLT^(-4)` `[a//b]=(ML^(1//2)T^(-2))/(MLT^(-4))=L^(-1//2)T^(2)`