1.

Find the dimensions of axxb in the relation ` P= (a -t^2)/(bsqrtx)`, wher x is distance t is time and P is power.

Answer» Correct Answer - `M^(-1)L^(-5//2)T^7`
`P = (a -t^2)/(bsqrtx)`
Dimension of a = `[T^2]`
Again, `(T^2)/(bsqrtx) =P, b =(T^2)/(Psqrtx) = (T^2)/([ML^2 T^(-3)]L^(1//2))`
`b = M^(-1) L^(-5//2) T^5`
`:. Axxb =T^2xxM^(-1)L^(-5//2) T^5= [M^(-1)L^(-5//2) T^7]`


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