1.

Find the dimensions of (i) force (ii) surface tension and (iii) momentum in terms of frequency, velocity and density as fundamental units.

Answer»

SOLUTION :Frequency `n=T^(-1),T=1/n`
Velocity `v=LT^(-1),L=vT=v/n`
Density `d=ML^(-3),M=dL^(3)=(dv^(3))/(n^(3))`
(i) Force `=MLT^(-2)=(dv^(3))/(n^(3))xxv/nxxn^(2)=(dv^(4))/(n^(2))`
(ii) SURFACE tension `=MT^(-2)=(dv^(3))/(n^(3))xxn^(2)=(dv^(3))/n`
(iii) Momentum `=MLT^(-1)=(dv^(3))/(n^(3))xxv/nxxn=(dv^(4))/(n^(3))`


Discussion

No Comment Found