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| 1. |
Find the dimensions of the potential and then the capacitance. Given, E = Vit and Q= CV |
| Answer» ANSWERSince charge on a capacitor with capacitance\xa0C\xa0is given by\xa0q=CV,therefore,\xa0C=Vq\u200b.Hence,\xa0[C]=Vq\u200b=[ML2T−3A−1][AT]\u200b=[M−1L−2A2T4] | |