1.

Find the direction cosines of the vector 'hati+2 hatj+3 hatk'

Answer»

SOLUTION :The DIRECTION COSINES are
`1/sqrt(1^2+2^2+3^2), 2/sqrt(1^2+2^2+3^2), 3/sqrt(1^2+2^2+3^2)`
i.e.,` 1/sqrt(14),2/sqrt(14 ,3/sqrt(14)`


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