InterviewSolution
Saved Bookmarks
| 1. |
Find the direction cosines of the vector 'hati+2 hatj+3 hatk' |
|
Answer» SOLUTION :The DIRECTION COSINES are `1/sqrt(1^2+2^2+3^2), 2/sqrt(1^2+2^2+3^2), 3/sqrt(1^2+2^2+3^2)` i.e.,` 1/sqrt(14),2/sqrt(14 ,3/sqrt(14)` |
|