1.

Find the direction cosines of two lines which are connected by the relations l + m + n = 0 and mn – 2nl – 2lm = 0.

Answer»

Given l + m + n = 0 ——— (1)

mn – 2nl – 2lm = 0 ——— (2)

From (1), l = –(m + n)

Substituting in (2),

mn + 2n(m + n) + 2m(m + n) = 0

mn + 2mn + 2n2 +2m2 + 2mn = 0

2m2 + 5mn + 2n2 = 0

(2m + n) (m + 2n) = 0

2m = –n or m = –2n

Case (i) : 2m1 = –n1

From l1 = –m1 – n1

= –m1 + 2m1 = m1

l1/1 = m1/1 = x1/-2

D.Rs of the first line are 1, 1, –2

D.Cs of this line are 1/√6,1/√6, - 2/√6

Case (ii) : m2 = –2n2

From (1) l2 = –m2 – n2 = +2n2 – n2 = n2 

l2/1 = m2/-2 = n2/1

d.cs of the second line are 1, –2, 1

d.cs of this line are 1/√6, -2/√6, 1/√6



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