Saved Bookmarks
| 1. |
Find the direction cosines of two lines which are connected by the relations l + m + n = 0 and mn – 2nl – 2lm = 0. |
|
Answer» Given l + m + n = 0 ——— (1) mn – 2nl – 2lm = 0 ——— (2) From (1), l = –(m + n) Substituting in (2), mn + 2n(m + n) + 2m(m + n) = 0 mn + 2mn + 2n2 +2m2 + 2mn = 0 2m2 + 5mn + 2n2 = 0 (2m + n) (m + 2n) = 0 2m = –n or m = –2n Case (i) : 2m1 = –n1 From l1 = –m1 – n1 = –m1 + 2m1 = m1 l1/1 = m1/1 = x1/-2 D.Rs of the first line are 1, 1, –2 D.Cs of this line are 1/√6,1/√6, - 2/√6 Case (ii) : m2 = –2n2 From (1) l2 = –m2 – n2 = +2n2 – n2 = n2 l2/1 = m2/-2 = n2/1 d.cs of the second line are 1, –2, 1 d.cs of this line are 1/√6, -2/√6, 1/√6 |
|