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InterviewSolution
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Find the displacement of a simple harmonic oscillator at which its P.E. is half of the maximum energy of the oscillator. |
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Answer» PE of oscillator, U = \(\frac{1}{2}mw^2y^2\) {y = displacement Maximum – energy of oscillator, E = \(\frac{1}{2}mw^2A^2\)} U = \(\frac{1}{2}E\) or \(\frac{1}{2}mw^2y^2\) = \(\frac{1}{2}mw^2A^2\) or y2 = \(\frac{A^2}{2}\) or y = \(\pm\frac{A}{\sqrt 2}\) |
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