Find the distance between (345)planes in a cubic lattice having length

1.	Find the distance between (345)planes in a cubic lattice having length 7.7A°
Answer» tance between (345) planes in a cubic lattice having length 7.7 A° is 1.089We know that, the distance can be REPRESENTED as : 1/ d² = h²/a² + k²/b² + l²/c² EQ(1)As per the question, a = b = c = 7.7 A° and h = 3, k = 4, l = 5Now, PUTTING the values in eq (1), we GET, 1/d² = 3²/7.7² + 4²/7.7² + 5²/7.7² = (3² + 4² + 5²) / 7.7² = 50/59.29 X 10 ⁻²⁰ = 0.843 x 10²⁰Now, d² = 1/ 0.843 x 10²⁰ d² = 1.186 d = 1.089

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