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Find the distances with the help of the number line given below.i. d(B, E)ii. d (J, J) iii. d(P, C) iv. d(J, H) v. d(K, O) vi. d(O, E) vii. d(P, J) viii. d(Q, B) |
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Answer» i. Co-ordinate of the point B is 2. Co-ordinate of the point E is 5. Since, 5 > 2 ∴ d(B, E) = 5 – 2 ∴ d(B, E) = 3 ii. Co-ordinate of the point J is -2. Co-ordinate of the point A is 1. Since, 1 > -2 ∴ d(J, A) = 1 – (-2) = 1 + 2 ∴ d(J, A) = 3 iii. Co-ordinate of the point P is -4. Co-ordinate of the point C is 3. Since, 3 > -4 ∴ d(P,C) = 3 – (-4) = 3 + 4 ∴ d(P,C) = 7 iv. Co-ordinate of the point J is -2. Co-ordinate of the point H is -1. Since, -1 > -2 ∴ d(J,H) = – 1 – (-2) = -1 + 2 ∴ d(J,H) = 1 v. Co-ordinate of the point K is -3. Co-ordinate of the point O is 0. Since,0 > -3 ∴ d(K, O) = 0 – (-3) = 0 + 3 ∴ d(K, O) = 3 vi. Co-ordinate of the point O is 0. ∴ Co-ordinate of the point E is 5. Since, 5 > 0 ∴ d(O, E) = 5 – 0 ∴ d(O, E) = 5 vii. Co-ordinate of the point P is -4. Co-ordinate of the point J is -2. Since -2 > -4 ∴ d(P, J) = -2 – (-4) = – 2+ 4 ∴ d(P, J) = 2 viii. Co-ordinate of the point Q is -5. Co-ordinate of the point B is 2. Since,2 > -5 ∴ d(Q,B) = 2 – (-5) = 2 + 5 ∴ d(Q, B) = 7 |
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