1.

Find the domain and range of the function \(\frac{x^2-4}{x-2}\).

Answer»

. Let y = \(\frac{x^2-4}{x-2}\) 

⇒ y = x + 2 when x ≠ 2

Now \(\frac{x^2-4}{x-2}\) is not defined only when x = 2, therefore

Domain of y = \(\frac{x^2-4}{x-2}\) is R - {2}. 

But y = x + 2 will take up all real values, but y = 4, when x = 2, (not possible) 

∴  Range of function is R – {4}.



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