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Find the domain and range of the function \(\frac{x^2-4}{x-2}\). |
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Answer» . Let y = \(\frac{x^2-4}{x-2}\) ⇒ y = x + 2 when x ≠ 2 Now \(\frac{x^2-4}{x-2}\) is not defined only when x = 2, therefore Domain of y = \(\frac{x^2-4}{x-2}\) is R - {2}. But y = x + 2 will take up all real values, but y = 4, when x = 2, (not possible) ∴ Range of function is R – {4}. |
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