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Find the domain of each of the following functions:f(x) = sin-1x2 |
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Answer» Domain of sin-1 lies in the interval [–1, 1]. Therefore domain of sin-1x2 lies in the interval [–1, 1]. –1 ≤ x2 ≤ 1 But x2 cannot take negative values, So, 0 ≤ x2 ≤ 1 -1 ≤ x ≤ 1 Hence domain of sin-1x2 is [–1, 1]. |
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