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                                    Find the domain of the following.1. f(x) = \(\frac{x^2 + 2x + 1}{x^2 - 8x + 12}\)2. f(x) = \(\frac{x^2 + 3x + 5}{x^2 -5x + 4}\) | 
                            
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Answer»  1. Given; f(x) = \(\frac{x^2 + 2x + 1}{x^2 - 8x + 12}\) The function is not defined at points where the denominator becomes zero. x2 – 8x +12 = 0 ⇒ (x – 6)(x – 2) = 0 ⇒ x = 2, 6 Therefore domain of fis R – {2, 6}. 2. Given; f(x) = \(\frac{x^2 + 3x + 5}{x^2 -5x + 4}\) The function is not defined at points where the denominator becomes zero. x2 – 5x + 4 = 0 ⇒ (x – 4)(x -1) = 0 ⇒ x = 1, 4 Therefore domain of f is R – {1, 4}.  | 
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