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Find the domain of the real-valued function: `f(x)=(x^(2)-x+1)/(x^(2)-5x+4)`. |
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Answer» We have, `f(x)=(x^(2)-x+1)/(x^(2)-5x+4)` Clearly, f(x) is defined for all real values of x except those at which `x^(2)-5x+4=0` But, `x^(2)-5x+4=0implies(x -1)(x-4)=0impliesx=1orx=4`. `:."dom "(f)=R-{1,4}`. |
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