InterviewSolution
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Find the eccentricity of the ellipse \(\rm \frac{x^2}{16} + \frac{y^2}{25} = 1\)?1. 12. 2/33. 3/54. 4/5 |
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Answer» Correct Answer - Option 3 : 3/5 Concept: Ellipse:
Calculation: Given: \(\rm \frac{x^2}{16} + \frac{y^2}{25} = 1\) Compare with the standard equation \(\rm \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) So, a2 = 16 and b2 = 25 ⇔ a = 4 and b = 5 (b > a) So, eccentricity = \(\rm \sqrt{1-\frac{a^2}{b^2}}\) = \(\sqrt{1-\frac{16}{25}}\) = 3/5 |
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