1.

Find the emissive power from "0.3 cm"^(2) surface of filament of bulb of tungsten at 3000 K temperature. Take e=0.4 for tungsten bulb.

Answer» <html><body><p></p>Solution :From Stefan - Boltzmaan law, <br/> `H=AesigmaT^(4)` <br/> `=0.3xx10^(-4)xx0.4xx5.67xx10^(-8)xx(3000)^(4)` <br/> `=55.1124` <br/> `:.` H `~~` <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> (Acc. to textbook <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a>)</body></html>


Discussion

No Comment Found