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Find the energy required to split `._(8)^(16)O` nucleus into four `alpha` - particles. The mass of an `alpha`- particle is 4.002603u and that of oxygen is 15.994915u. |
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Answer» The energy required to split O = [Total mass of the products - Total mass of the reactants] `c^(2)` Mass of four `._(2)^(4)He` - Mass of `._(8)^(16)O xx c^(2)` `=[(4xx4.002603)-15.994915]u xx c^(2)` `= [1.6010412 - 15.994915] u xx c^(2)` `= (0.015497) 931.5 MeV = 14.43 MeV` |
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