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Find the equation of a circle with: centre at (-3, -2) and radius 6. |
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Answer» The equation of a circle with centre at (h, k) and radius ‘r’ is given by (x – h)2 + (y – k)2 = r2 Here, h = -3, k = -2 and r = 6 ∴ The required equation of the circle is [x – (-3)]2 + [y – (-2)]2 = 62 ⇒ (x + 3)2 + (y + 2)2 = 36 ⇒ x2 + 6x + 9 + y2 + 4y + 4 – 36 = 0 ⇒ x2 + y2 + 6x + 4y – 23 = 0 |
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