1.

Find the equation of a straight line in the plane vecr.vecn=d which is parallel to vecr.vecn=d("where "vecn.vecb=0).

Answer»

`vecr=veca+((d-veca.VECN)/(N^(2)))vecn+lamdavecb`
`vecr=veca+((d-veca.vecn)/(n))vecn+lamdavecb`
`vecr=veca+((veca.vecn-d)/(n^(2)))vecn+lamdavecb`
`vecr=veca+((veca.vecn-d)/(n))vecn+lamdavecb`

Solution :Foot of the perpendicular from POINT `A(veca)` on the plane `vecr*vecn=d` is `veca+ ((d-veca*vecn))/(|vecn|^(2))vecn`
Therefore, EQUATION of the LINE parallel to `vecr=veca+lamdavecb` in the plane `vecr*vecn =d` is given by
`""vecr=veca+ ((d-veca*vecn))/(|vecn|^(2))vecn+lamdavecb`


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