1.

Find the equation of circles determined by the following conditions. The centre at (-1, 4) and circle tangent to y-axis.

Answer»

Solution : `therefore` RADIUS = 2
`(x-h)^2 + (y-k)^2 = a^2`
or, `(x+1)^2 + (y-4)^2 = 1`
or, `x^2 + 1 + 2x + y^2 + 16 - 8y =1`
`x^2 + y^2 + 2x -8y +16 = 0`


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