Saved Bookmarks
| 1. |
Find the equation of circles determined by the following conditions. The centre at (-1, 4) and circle tangent to y-axis. |
Answer» Solution : `therefore` RADIUS = 2 `(x-h)^2 + (y-k)^2 = a^2` or, `(x+1)^2 + (y-4)^2 = 1` or, `x^2 + 1 + 2x + y^2 + 16 - 8y =1` `x^2 + y^2 + 2x -8y +16 = 0` |
|