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Find the equation of circles determined by the following conditions. The radius is 5 and circle is tangent to both axes. |
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Answer» Solution :As the circle is tangent to both the axes, we have its centre at (5, 5). `THEREFORE` EQUATION of the circle is or, `(x+-5)^2+(y+-5)^2=25` or, `x^2+25+-10x+y^2+25+-10y=25` or, `x^2+y^2+-10x+-10y+25=0` |
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