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Find the equation of circles determined by the following conditions.The centre at (-2, 3) and passing through origin. |
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Answer» Solution :Centre at (-2, 3) and circle PASSES through origin. `THEREFORE` RADIUS of the circle = `sqrt((-2)^2 + 3^2) = sqrt(13)` `therefore` Equation of the circle is `(x-h)^2 + (y-k)^2 = a^2` or, `(x+2)^2 + (y-3)^2 = 13` |
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