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Find the equation of circles determined by the following conditions. The centre at (3, 2) and circle is tangent to x-axis. |
Answer» Solution : `THEREFORE` Radius = 2 `therefore` Eqn. of the circle is `(x-h)^2 + (y-k)^2 = a^2` or, `(x-3)^2 + (y-2)^2 = 4` or, `x^2 + 9 - 6X + y^2 + 4 - 4Y = 4` `x^2 + y^2 - 6x - 4y + 9 = 0` |
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