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Find the equation of hyperbola whose vertices at (±6, 0) and foci at (±8, 0). |
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Answer» Vertices are of the form (±a, 0), hence it is a horizontal hyperbola. So, the equation is of the form: x2/a2 – y2/b2 = 1 …..(1) Given: vertices of hyperbola (±6, 0) Here a = 6 Again, Foci is of the form (±c, 0) Given: foci of hyperbola at (±8, 0) ⇒ c = 8 Find b: We know, c2 = a2 + b2 64 = 36 + b2 or b2 = 64 – 36 = 28 Equation (1)⇒ x2/36 – y2/28 = 1 Which is required equation. |
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