1.

Find the equation of hyperbola whose vertices at (±6, 0) and foci at (±8, 0).

Answer»

Vertices are of the form (±a, 0), hence it is a horizontal hyperbola.

So, the equation is of the form: x2/a2 – y2/b2 = 1 …..(1)

Given: vertices of hyperbola (±6, 0)

Here a = 6

Again,

Foci is of the form (±c, 0)

Given: foci of hyperbola at (±8, 0)

⇒ c = 8

Find b:

We know, c2 = a2 + b2

64 = 36 + b2

or b2 = 64 – 36 = 28

Equation (1)⇒

x2/36 – y2/28 = 1

Which is required equation.



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