Saved Bookmarks
| 1. |
Find the equation of plane which cuts equal intercepts from the axes and passes through the point (2, 3, 5). |
|
Answer» Let the plane cuts intercept of 'a' unit on axes. So, equation of the plane be x/a + y/b + z/a = 1 x + y + z = a If this plane passes through the point P(2,3,5) then 2 + 3 + 5 = a a = 10 Hence, require equation of plane is x + y + z = 10 |
|