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Find the equation of tangent to the circle x2 + y2 – 2ax = 0 at the point (a(1 + cosα), a sinα) |
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Answer» Equation of tangent of x2 + y2 – 2ax = 0 at (a(1 + cosα),asinα) is ax(1 + cosα) + aysin α – a(x + a(1 + cosα)) = 0 ax + axcosα + aysinα – ax – a2 (1+cosα) = 0 axcosα + aysinα = a2 (1 + cosα) xcosα + ysinα = a(1 + cosα) |
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