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Find the equation of the circle concentric with the circle `x^2 + y^2 - 4x - 6y - 3 = 0` and which touches the y axis

Answer» Correct Answer - ` x ^(2) + y ^(2)- 4x - 6y + 9 = 0 `
Centre of the given circle is ` (2, 3 )`
Centre of the required circle is ` (2, 3 )`
The required circle touches the y- axis, so its radius = 2.
`therefore ` the required equation is ` (x - 2 ) ^(2) + ( y- 3 )^(2) = 2 ^(2)`.


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