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Find the equation of the circle cuts intercepts of the length ‘a’ and ‘b’ on axes and passes through the origin |
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Answer» Intercepts a and b on axes that implies circle passes through the points (a, 0) and (0, b) passing through origin ⇒ c = 0 (a, 0) a2 + 2ga = 0 ⇒ g = \(\frac{a}{2}\) (0, -b) b2 + 2fb = 0 ⇒ f = \(\frac{-b}{2}\) ∴ The required equation is x2 + y2 – ax – by = 0. |
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