1.

Find the equation of the circle cuts intercepts of the length ‘a’ and ‘b’ on axes and passes through the origin

Answer»

Intercepts a and b on axes that implies circle passes through the points (a, 0) and (0, b) passing through origin 

⇒ c = 0 

(a, 0) a2 + 2ga = 0 ⇒ g = \(\frac{a}{2}\)

(0, -b) b2 + 2fb = 0 ⇒ f = \(\frac{-b}{2}\)

∴ The required equation is x2 + y2 – ax – by = 0.



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