1.

Find the equation of the circle passing through the points A(0, 1), B(2, 3) and C(−2, 5).

Answer»

Let S  x2 + y2 + 2gx + 2fy + c = 0 be the circle passing through points A, B and C. Therefore

2f + c = -1

4g + 6f + c = -13

-4g + 10f + c = -13

-4g +10f + c = -29     .......(1)

Solving the system of equations provided in Eq. (1), we get get g = 1/3, f = −10/3 and c = 17/3 so that the equation of the circle is

x1 + y2 + 2/3x - 20/3y + 17/3 = 0

3x2 + 3y2 + 2x - 20y + 17 = 0

Note: Under the given hypothesis, to find the equation of the circle, it is sufficient if we find its centre and radius or assume the circle as x2 + y2 + 2gx + 2fy + c = 0 and find the values of g, f and c.



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