InterviewSolution
Saved Bookmarks
| 1. |
Find the equation of the circle passing through the points A(0, 1), B(2, 3) and C(−2, 5). |
|
Answer» Let S ≡ x2 + y2 + 2gx + 2fy + c = 0 be the circle passing through points A, B and C. Therefore 2f + c = -1 4g + 6f + c = -13 -4g + 10f + c = -13 -4g +10f + c = -29 .......(1) Solving the system of equations provided in Eq. (1), we get get g = 1/3, f = −10/3 and c = 17/3 so that the equation of the circle is x1 + y2 + 2/3x - 20/3y + 17/3 = 0 3x2 + 3y2 + 2x - 20y + 17 = 0 Note: Under the given hypothesis, to find the equation of the circle, it is sufficient if we find its centre and radius or assume the circle as x2 + y2 + 2gx + 2fy + c = 0 and find the values of g, f and c. |
|