Related InterviewSolutions

• If the centre of the circle is (-a, -b) and radius is √(a2 - b2) then the equation of circle is: (a) x2 + y2 + 2ax + 2by + 2b2 = 0 (b) x2 + y2 + 2ax + 2by – 2b2 = 0 (c) x2 + y2 – 2ax – 2by – 2b2 = 0 (d) x2 + y2 – 2ax – 2by + 2b2 = 0
• The locus of the point P which moves such that P is always at equidistance from the line x + 2y + 7 = 0: (a) x + 2y + 2 = 0 (b) x – 2y + 1 = 0 (c) 2x – y + 2 = 0 (d) 3x + y + 1 = 0
• ax2 + 4xy + 2y2 = 0 represents a pair of parallel lines then ‘a’ is: (a) 2 (b) -2(c) 4 (d) -4
• The equation of directrix of the parabola y2 = -x is: (a) 4x + 1 = 0 (b) 4x – 1 = 0 (c) x – 1 = 0 (d) x + 4 = 0
• If m1 and m2 are the slopes of the pair of lines given by ax2 + 2hxy + by2 = 0, then the value of m1 + m2 is: (a) \(\frac{2h}{b}\)(b) -\(\frac{2h}{b}\)(c) \(\frac{2h}{a}\)(d) -\(\frac{2h}{a}\)
• If kx2 + 3xy – 2y2 = 0 represent a pair of lines which are perpendicular then k is equal to: (a) \(\frac{1}{2}\)(b) -\(\frac{1}{2}\)(c) 2(d) -2
• If the lines 2x – 3y – 5 = 0 and 3x – 4y – 7 = 0 are the diameters of a circle, then its centre is: (a) (-1, 1) (b) (1, 1) (c) (1, -1) (d) (-1, -1)
• Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola (a) y2 = 20x, (b) x2 = 8y, (c) x2 = -16y
• Find the vertex, focus, axis, directrix, and the length of the latus rectum of the parabola y2 – 8y – 8x + 24 = 0.
• The eccentricity of the parabola is: (a) 3 (b) 2 (c) 0(d) 1