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Find the equation of the circle whose centre is at (4,-2) and passing through the origin (0,0) |
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Answer» C = (4, -2) & r = \(\sqrt {4^2 + (-2)^2} = \sqrt{16 + 4} = \sqrt{20}\) Equation of the circle (x + 4)2 + (y + 2)2 = (√20) ⇒ x2 + 16 – 8x + y2 + y + 4y – 20 = 0 ⇒ x2 + y2 – 8x + 4y = 0 |
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