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Find the equation of the circle with center at the origin and radius 5. Write the coordinates of eight points on this circle. |
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Answer» Equation of the circle = (x – 0)2 + (y – 0)2 = 52 = x2 + y2 = 25 x2 = 25 – y2 x = \(\sqrt{25-y^2}\) y = 0 x = 5 (5, 0), (–5, 0) y = 5 x = 0 (0, 5), (0, –5) y = 3 x = 4 (4, 3), (4, 3) y = 4 x = 3 (3, 4), (3, –4) Coordinates of points on the circle (5, 0), (–5, 0), (0, 5), (0, -5), (4, 3), (4, 3), (3, 4), (3, 4). |
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