Saved Bookmarks
| 1. |
Find the equation of the circle with centre at (2, 1) and passing through (0, -1). |
|
Answer» Given Centre = C (2, 1) & Let P = (0, -1) Here r = CP = \(\sqrt{(0 - 2)^2 + (-1 - 1)^2} = \sqrt{4 + 4} \) = \(\sqrt 8 \) units Equation of the circle with centre (2, 1) & r =(\(\sqrt 8 \))2 is (x – 2)2 + (y – 1)2 = \(\sqrt 8 \) x2 + 4x + y2 + 1 – 2y = 8 x2 + y2 – 4x – 2y – 3 = 0. |
|