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Find the equation of the hyperbola whose asymptotes are `3x=+-5y` and the vertices are `(+-5,0)`A. `3x^(2)-5y^(2)=25`B. `5x^(2)-3y^(2)=25`C. `9x^(2)-25y^(2)=225`D. `225x^(2)-9y^(2)=225` |
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Answer» The equation of the hyperbola having `3x+5y=0` and `3x-5y=0` as it asymptotes is ltrgt `(3x+5y)(3x-5y)+lambda=0`……..`(i)` It passes through `(5,0)` `implies225-0+lambda=0implieslambda=-225` Substituting the value of `lambda` in `(i)`, we get `9x^(2)-25y^(2)=225` as the equation of the hyperbola |
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