InterviewSolution
Saved Bookmarks
| 1. |
Find the equation of the hyperbola with eccentricity `sqrt(2)` and the distance between whose foci is 16. |
|
Answer» Correct Answer - `x^(2)-y^(2)=32` `2c=16hArr c=8 ." " Also , e=sqrt(2)` `"Now" , e=(c )/(a)implies a=(c )/(e) =(8)/(sqrt(2))=4sqrt(2)`. `therefore b^(2)=(c^(2)-a^(2))=(64-32)=32.` Thus , `a^(2)=32 and b^(2)=32.` |
|