1.

Find the equation of the hyperbola with eccentricity `sqrt(2)` and the distance between whose foci is 16.

Answer» Correct Answer - `x^(2)-y^(2)=32`
`2c=16hArr c=8 ." " Also , e=sqrt(2)`
`"Now" , e=(c )/(a)implies a=(c )/(e) =(8)/(sqrt(2))=4sqrt(2)`.
`therefore b^(2)=(c^(2)-a^(2))=(64-32)=32.`
Thus , `a^(2)=32 and b^(2)=32.`


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