1.

Find the equation of the hyperbola with vertices at (0, ±5) and foci at (0, ±8).

Answer»

Vertices are of the form (0, ±a), hence it is a vertical hyperbola.

So, the equation is of the form: y2/a2 – x2/b2 = 1 …..(1)

Given: vertices of hyperbola (0, ±5)

Here a = 5

Again,

Foci is of the form (0, ±c)

Given: foci of hyperbola at (0, ±8)

⇒ c = 8

Find b:

We know, c2 = a2 + b2

64 = 25 + b2

or b2 = 39

Equation (1)⇒

y2/25 – x2/39 = 1

Which is required equation.



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