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Find the equation of the hyperbola with vertices at (0, ±5) and foci at (0, ±8). |
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Answer» Vertices are of the form (0, ±a), hence it is a vertical hyperbola. So, the equation is of the form: y2/a2 – x2/b2 = 1 …..(1) Given: vertices of hyperbola (0, ±5) Here a = 5 Again, Foci is of the form (0, ±c) Given: foci of hyperbola at (0, ±8) ⇒ c = 8 Find b: We know, c2 = a2 + b2 64 = 25 + b2 or b2 = 39 Equation (1)⇒ y2/25 – x2/39 = 1 Which is required equation. |
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