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Find the equation of the line parallel to the line 3x – 4y + 2 = 0 and passing through the point (-2, 3). |
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Answer» The equation of the line parallel to the line 3x – 4y + 2 = 0 is of the form 3x – 4y + k = 0. Since it passes through (-2, 3), we have; 3(-2) – 4(3) + k = 0 ⇒ -6 – 12 + k = 0 ⇒ -18 + k = 0 ⇒ k = 18 Hence the equation is 3x – 4y + 18 = 0. |
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