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Find the equation of the line x – 7y + 5 = 0 perpendicular to the line and having x-intercept 3. |
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Answer» The equation of the perpendicular line will be 7x + y + k = 0. Since x-intercept is 3, the line passes through the point (3, 0). So we have; 7(3) + 0 + k = 0 ⇒ 21 + 0 + k = 0 ⇒ k = -21 Therefore the equation is 7x + y – 21 = 0. |
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