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Find the equation of the locus of the point which is at a constant distance of 5 units from the fixed point (-2,3). |
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Answer» Let A = (-2,3) and let P = (x,y). Now AP = 5 (AP)2 = 25 (x + 2)2 + (y - 3)2 = 25 x2 + y2 + 4x - 6y - 12 = 0 The equation of the locus is x2 + y2 + 4x – 6y – 12 = 0. |
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