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Find the equation of the normal to the circle x2 + y2 = 2x which is parallel to the line x + 2y = 3 |
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Answer» Equation of normal at (x1 ,y1 ) of x2 + y2 – 2x = 0 is x - x1/x1 - 1 = y - y1/y1 - 0 (∴ x - x1/ax1 + g = y - y1/by1 + f) Slope of this equation is y1/x1 - 1 Slope of x + 2y = 3 is -1/2 Since given that normal is parallel to x + 2y = 3 ∴ y1/x1 - 1 = -1/2 y1 = – x1 + 1 therefore locus of (x1 , y1 ) is x1 + 2y1 = 1 It is the equation of normal |
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