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Find the equation of the parabola satisfying the following conditions;1. Focus(6, 0); directrix x = – 62. Vertex (0, 0); Focus (3, 0)3. Vertex (0, 0) passing through (2, 3) and axis along x-axis |
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Answer» 1. Since the focus (6, 0) lies on the x-axis, therefore x-axis is the axis of parabola. Also the directrix is x = – 6, ie; x = – a And focus (6, 0), ie; (a, 0) Therefore the equation of the parabola is y2 = 4ax ⇒ y2 = 24x. 2. The vertex of the parabola is at (0, 0) and focus is at (3, 0). Then axis of parabola is along x-axis. So the parabola is of the form y2 = 4ax . The equation of the parabola is y2 = 12x. 3. The vertex of the parabola is at (0, 0) and the axis is along x-axis. So the equation of parabola is of the torn y2 = 4ax . Since the parabola passes through point (2, 3) Therefore, 32 = 4a × 2 ⇒ a = \(\frac{9}{8}\) The required equation of the parabola is y2 = 4 × \(\frac{9}{8}\) x ⇒ y2 = \(\frac{9}{2}\)x. |
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