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Find the equation of the plane passing through the intersection of the planes 3x - y + 2z - 4 = 0 and x + y + z + 2 = 0 and the point (2, 2, 1) |
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Answer» Equation of plane passing through intersection of the plane is (3x - y + 2z - 4) + λ (x + y + z + 2) = 0 This plane pass through (2, 2, 1) 3(2) - 2 + 2(1) -4 + λ(2 + 2 + 1 + 2) = 0 2 + 7λ = 0 λ = -2/7 Required equation of plane is (3x - y + 2z - 4) + (x + yz + 2) + 0 [xly by 7] 21x - 7y + 14z - 28 - 2x - 2y - 2z - 4 = 0 19x - 9y + 12z = 32 |
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