1.

Find the equation of the plane passing through the intersection of the planes 3x - y + 2z - 4 = 0 and x + y + z + 2 = 0 and the point (2, 2, 1)

Answer»

Equation of plane passing through intersection of the plane is (3x - y + 2z - 4) + λ (x + y + z + 2) = 0 

This plane pass through (2, 2, 1) 

3(2) - 2 + 2(1) -4 + λ(2 + 2 + 1 + 2) = 0 

2 + 7λ = 0 

λ = -2/7

Required equation of plane is 

(3x - y + 2z - 4) + (x + yz + 2) + 0 [xly by 7] 

21x - 7y + 14z - 28 - 2x - 2y - 2z - 4 = 0 

19x - 9y + 12z = 32



Discussion

No Comment Found

Related InterviewSolutions