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Find the equation of the plane passing through the line of intersection of the planes 2x + y - Z = 3,5x - 3y + 4z + 9 = 0 and parallel to the line `(x-1)/2=(y-3)/4=(z-5)/5` |
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Answer» `C=2*x+y-z-3=0``d=5*x-3*y=4*z+9=0` so,(C+`lamda`d) let `lamda`=A equation of plane passing through the line of the intersection of these two plane `(2*x+y-z-3)+A(5*x-3*y+4*z+9)`....(i)equation of the line= `(x-1)/2=(y-3)/4=(z-5)/5` `(2,4,5)` are the direction ratiosEquation of the plane=`2(2+5A)+4(1-3A)+5(4A-1)+9A-3=0` on solvingA=-1/6putting in equation (i)you will get the equation equation of the plane`7*x+9*y-10*z=0` ...Ans |
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